On Tue, 2003-10-07 at 17:49, Tom Munro Glass wrote:
> I'm trying to parse a log file, very similar to /var/log/messages, where there
> are some quite well defined fields at the start of the line, but then some
> free form text at the end. I can extract and process the first few fields
> quite easily with $1 $2 $3 etc, but how can I get awk to print out the rest
> of the line after field $3 and ignore any delimiter characters in the free
> from text?
>
> For example, consider the input
>
> 01/10/2003 01:02:03 MyCommand: Here is some free form text from command
>
> When parsed with awk:
>
> $1 = date (01/10/2003)
> $2 = time (01:02:03)
> $3 = command (MyCommand:)
> ?? = Here is some free form text from command
>
> Any ideas?
Its not a good answer, but
echo "01/10/2003 01:02:03 MyCommand: Here is some free form text from
command" | awk '{ print $3 " " $4 " " $5 " " $6 " " $7 " " $8 " " $9 " "
$10 " " $11 ........ }'
would do the trick. Or someone else will suggest Python or Perl or
$languageofchoice.
I don't think you can do a ' { print $4- } ' in awk
