On Thu, Jun 23, 2005 at 12:54:34AM +0100, Simos Xenitellis wrote:
> Roger Leigh wrote:
>
> >A while back, I made the useful discovery that GCC accepts UTF-8
> >encoded C source by default, and in the generated object code uses
> >UTF-8 for narrow (char) strings, and UTF-32/UCS-4 for wide (wchar_t)
> >strings.
> >
> Googling for "gcc utf-8" brings up a discussion from this list (Dec
> 2004) which references the GCC documentation.
> The archive of that discussion starts at
> http://mail.nl.linux.org/linux-utf8/2004-11/index.html#00008
>
> The behaviour of the compiler regarding Unicode strings can be
> controlled with preprocessor options.
> The page for this is
> http://gcc.gnu.org/onlinedocs/gcc-4.0.0/gcc/Preprocessor-Options.html#Preprocessor-Options
That's interesting, thanks. I'm still a little confused, though.
#include <locale.h>
#include <stdio.h>
#include <wchar.h>
int
main (void)
{
setlocale (LC_ALL, "");
printf("‘Name1’\n");
printf("%ls\n", L"‘Name2’");
fwide(stderr, 1);
fwprintf(stderr, L"‘Name3’\n");
fwprintf(stderr, L"%s\n", "‘Name4’");
printf("‘Name5’\n");
return 0;
}
Try running this in a C locale!
$ ./test
'Name3'
‘Name1’
‘Name5’
Only 'Name3' printed as I would have expected. The others printed
UTF-8, or nothing at all.
Regards,
Roger
--
Roger Leigh
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--
Linux-UTF8: i18n of Linux on all levels
Archive: http://mail.nl.linux.org/linux-utf8/
