Pkshih <[email protected]> writes: > On Fri, 2018-06-29 at 10:30 +0300, Kalle Valo wrote: >> Pkshih <[email protected]> writes: >> >> > On Tue, 2018-05-29 at 08:18 +0300, Kalle Valo wrote: >> >> <[email protected]> writes: >> >> >> > >> > Because C2H data is little endian order, the struct will look like >> > struct foo { >> > #ifdef __LITTLE_ENDIAN >> > u8 bar:4; >> > u8 koo:4; >> > #else >> > u8 koo:4; >> > u8 bar:4; >> > #endif >> > } >> >> With u8 you don't need endian check, right? I would assume that with >> both little and big endian bar and koo would be in the same place. > > I think u8 with bitfield would be different between little and big endian > machines.
To me that does not make any sense, I have never heard about bit endianness any of the devices I have worked on. https://en.wikipedia.org/wiki/Endianness -- Kalle Valo
