Hi Joe 2007/3/26, [EMAIL PROTECTED] <[EMAIL PROTECTED]>: > This is a silly question but, when I see something like this (2<<20) > in raminit.c it is saying to change bit 20 to a value of 2?? Is that > correct?? That would have to be a binary value than right? Than what > would that look like?? Just trying to understand the whole registry > setting thing better. >
This is a shift operation, then you need think it in binary: 2 = 10 (binary) 10 << 20 = 1000000000000000000000 This operation is just to set the 22th bit. This is equivalent to 1 << 21. More info read about shift operation: http://en.wikipedia.org/wiki/Arithmetic_shift > Thanks - Joe > Cheers, Alan -- linuxbios mailing list [email protected] http://www.linuxbios.org/mailman/listinfo/linuxbios
