Quoting Myles Watson <[EMAIL PROTECTED]>: > > >> > col = 9 /* SPD byte 4: Number of Column Addresses */ >> > bus_width = 64 /* SPD byte 6: Data Width of Assembly */ >> > >> > page_size = (2^col)*bus_width >> >> 2^9 = 512 >> >> > 5184 = 81 * 64 >> >> 512 * 64 = 32K >> >> Myles > > Sorry, that should have been 32K bits, since you are multiplying by 64 bits. > Then dividing by 8 bits/byte = 4 KB. > > Myles > >> >> > >> > Which is not correct because the DIMM has a 4k page size. >> > (According to it's datasheet). > > > > Your right, Duh I was doing 9^2 = 81 :-)
col = 9 /* SPD byte 4: Number of Column Addresses */ bus_width = 64 /* SPD byte 6: Data Width of Assembly */ bit_page_size = ((2^col) * bus_width) */ convert to KB */ page_size = ((bit_page_size / 8) >> 10) = 4KB Sweet, this is a much easier way to calculate the DRA ? DRAM Row Attribute Register!! One last question, A normal SDRAM DIMM should always have SPD byte 6 = 64 and ECC should have SPD byte 6 = 72. Is this correct?? Thanks for all the help - Joe -- linuxbios mailing list [email protected] http://www.linuxbios.org/mailman/listinfo/linuxbios
