> Second thing > My BIOS image is ok abt 10 KB (suppose) > and i have chip of 256KB So my image is like this > > And I want to know where to place this small code in BIG chip >
LInuxbios has to be located so that the reset vector code is at the right location. The PC reset vector is 0xfffffff0. So the linuxbios image has to occupy the very top of your rom chip. So if your flash is 256Kb = 262144 bytes. your lb size 10kb = 10240 bytes Offset in flash chip to start programming = flash size - linubbios size = 262144 - 10240 = 251904 So as you can see you need to know the _exact_ size of your image file even if you are only 1 byte off it still won't work. Basically you have to make sure that the last 16 bytes of the linuxbios image match the last 16 bytes of your flash chip. Everything else in the linuxbios image should be relative. -- Richard A. Smith _______________________________________________ LinuxBIOS mailing list [email protected] http://www.openbios.org/mailman/listinfo/linuxbios
