hi,
delta error amish..
that should b for char ** arg;
but nikhil got char *arg[4]; :-)
nikhil.. any other methods .. let us c
...
char arg1[BUF_SIZE];
char *arg[4]
int i;
for(i=0; i<4;i++)
arg[i] = &arg1[0];
.. /* oops but i m burying all args in to same grave ;-) */
so ..
...
char arg1[BUF_SIZE], arg2[BUF_SIZE], arg3[BUF_SIZE],
arg4[BUF_SIZE];
arg[0] = &arg1[0];
arg[1] = &arg1[0];
arg[2] = &arg1[0];
arg[3] = &arg1[0];
... /* ohh.. that could b painful digging if too many to b
buried */
...
char arg1[BUF_SIZE * 4]
for(i=0; i<4; i++)
arg[i] = &arg1[i * BUF_SIZE];
... /* gosh.. if u bury anybody longer than BUF_SIZE.. u r
tampering others grave */
for(i=0;i<4;i++){
arg[i] = (char *) calloc(BUF_SIZE, sizeof (char));
}
/* ok .. looking nice.. but then if i don't clear the grave
after buried r (scope)deceased.. my burial ground will b
filled too */
#define NO_OF_ARGS
char **arg;
arg = (char **) calloc (NO_OF_ARGS, sizeof(char *));
for(i=0;i<NO_OF_ARGS; i++){
arg[i] = (char *) calloc (BUF_SIZE, sizeof(char));
}
/* ok.. i m digging the burial ground too !*/
caveat: if you dig, remember to cover later (think free!!)
ok.. above is just for fun..
no offence implied.
-shailesh
--- Amish Mehta <[EMAIL PROTECTED]> wrote:
> Hi,
>
> You got divine hands :-). Though it worked, you should
> still allocate
> memory to arg itself for holding array of pointers.
> Something like
>
> arg = (char **) malloc(sizeof(char *) * 6);
> arg[5] = NULL;
>
> Amish.
>
> Nikhil Joshi wrote:
> > >Hi!
> >success afterall ...
> >I used following to allocate memory to arg
> >
> >for (i=1;i<4;i++)
> > if ((arg[i] = (char *) malloc (30)) == NULL)
>
>
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