On Thu, Jun 18, 2009 at 9:03 AM, Mayank wrote:
> I'm sorry if this question has been asked before but I couldn't find
> any appropriate answer elsewhere and hence this post. Today while doing some
> calculation using bc I found a very peculiar thing. I was performing an
> operation -2 % -3 and the software reported the answer as -2. Now -2 > -3
> and if I remember correctly then in divison operation the remainder is less
> than the divisor. So how come in this case the answer is not coming
> properly. Is it a software flaw or there is some mistake in my understanding
> of the division operation ?
>From the bc man page:
"expr % expr
The result of the expression is the "remainder" and it
is computed in the following way. To compute a%b, first a/b is
computed to scale digits. That result is used to compute a-(a/b)*b to
the scale of the maximum of scale+scale(b) and scale(a). If scale is
set to zero and both expressions are integers this expression is the
integer remainder function."
Now, the default "scale" in bc is 0, which takes all fractions to the
integer preceding them. e.g.
--
Kumar
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