hardcoded SIGSEGV in __die() ?

[Joakim Tjernlund]

In __die(), see below, there is this call to notify_send() with SIGSEGV 
hardcoded, this seems odd
to me as the variable "err" holds the true signal(in my case SIGBUS)
Should not SIGSEGV be replaced with the true signal no.?

  Jocke

static int __die(const char *str, struct pt_regs *regs, long err)
{
        printk("Oops: %s, sig: %ld [#%d]\n", str, err, ++die_counter);

        if (IS_ENABLED(CONFIG_CPU_LITTLE_ENDIAN))
                printk("LE ");
        else
                printk("BE ");

        if (IS_ENABLED(CONFIG_PREEMPT))
                pr_cont("PREEMPT ");

        if (IS_ENABLED(CONFIG_SMP))
                pr_cont("SMP NR_CPUS=%d ", NR_CPUS);

        if (debug_pagealloc_enabled())
                pr_cont("DEBUG_PAGEALLOC ");

        if (IS_ENABLED(CONFIG_NUMA))
                pr_cont("NUMA ");

        pr_cont("%s\n", ppc_md.name ? ppc_md.name : "");

        if (notify_die(DIE_OOPS, str, regs, err, 255, SIGSEGV) == NOTIFY_STOP)
                return 1;

        print_modules();
        show_regs(regs);

        return 0;
}