> On 5 Feb 2026, at 19:43, Danilo Krummrich <[email protected]> wrote:
> 
> On Thu Feb 5, 2026 at 11:31 PM CET, Gary Guo wrote:
>> On Thu Feb 5, 2026 at 7:05 PM GMT, Danilo Krummrich wrote:
>>>  (1) Devices are either little-endian or big-endian. Hence, having to write
>>> 
>>> io.big_endian().write()
>>> 
>>>      is excessive, we always want big-endian for a big-endian device.
>> 
>> You don't need to always write this. You just need to do `big_endian()` once
>> when you obtain the io, and then keep using `BigEndian<Mmio>` instead of just
>> `Mmio`, and the rest of code is still `.write()`.
> 
> <snip>
> 
>>>  (2) It is error prone, if you forget to call big_endian() first, it is a 
>>> bug.
>> 
>> Moot point when `big_endian()` is only done once.
> 
> Well, you need to do it at least once per driver entry point. For DRM IOCTLs 
> for
> instance you also have to consider that it is always Devres<Mmio>.
> 

Well, this is also the case for relaxed(). I basically made peace with the fact 
that

let mmio = mmio.relaxed();
< use mmio >

is going to be a reality per driver entrypoint, unless I misunderstood?

— Daniel

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