> static void mlx4_bf_copy(unsigned long *dst, unsigned long *src,
unsigned bytecnt) {
> + int i;
> + __le32 *psrc = (__le32 *)src;
> +
> + /*
> + * the buffer is already in big endian. For little endian
machines that's
> + * fine. For big endain machines we must swap since the chipset
swaps again
> + */
> + for (i = 0; i < bytecnt / 4; ++i)
> + psrc[i] = le32_to_cpu(psrc[i]);
> +
> __iowrite64_copy(dst, src, bytecnt / 8);
> }
That code looks horrid...
1) I'm not sure the caller expects the buffer to be corrupted.
2) It contains a lot of memory cycles.
3) It looked from the calls that this code is copying descriptors,
so the transfer length is probably 1 or 2 words - so the loop
is inefficient.
4) ppc doesn't have a fast byteswap instruction (very new gcc might
use the byteswapping memery access for the le32_to_cpu() though),
so it would be better getting the byteswap done inside
__iowrite64_copy() - since that is probably requesting a byteswap
anyway.
OTOH I'm not at all clear about the 64bit xfers....
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