hi all
I have powerpc 604 and MVME 3604 and I want to run the linux 2.4.18 on that
platform.
So i follow the following instruction to compile 2.4.18 for powerpc604
Install crosstool for the powerpc604 (from kegel.com) in /opt/crosstool
Then i download 2.4.18 kernel.
3. then i go to kernel source directory and run make ARCH=ppc xconfig
4. then make ARCH=ppc CROSS_COMPILE=powerpc-604-linux-gnu- dep bzImage
5. i found following images in my kernel source directory
i.e <home>/linux/2.4.18/arch/ppc/boot/images
vmlinux
zImage.chrp
vmlinux.coff
zImage.pmac
zImage.prep
Now What is the step to boot with this images ?
which is the main image to boot ?
whether it will give me command prompt?
I am using tornado for interfacing with powerpc (PPC604)
Regards
Nirav
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