my cpu is 860T, using bootm command boot a linux kernel image, the following message print by smc1:
bootm 300000 ## Booting image at 00300000 ... Image Name: Linux-2.6.20.14 Image Type: PowerPC Linux Kernel Image (gzip compressed) Data Size: 1081591 Bytes = 1 MB Load Address: 00100000 Entry Point: 00100000 Verifying Checksum ... OK Uncompressing Kernel Image ... OK ## Current stack ends at 0x01D5DB10 => set upper limit to 0x00800000 No initrd ## Transferring control to Linux (at address 00100000) ... then, the program has no response. i debug it througth BDM, in u-boot function "do_bootm_linux", execute at "kernel = (void (*)(bd_t *, ulong, ulong, ulong, ulong))hdr->ih_ep", the program branch to address "0x00000000", the code is shown as following: 00000000 mr r31,r3 00000004 mr r30,r4 00000008 mr r29,r5 0000000C mr r28,r6 00000010 mr r27,r7 00000014 bl 0x000020C8 00000018 mfmsr r0 0000001C ori r0,r0,0x30 00000020 mtspr SRR1,r0 00000024 lis r0,[EMAIL PROTECTED] 00000028 ori r0,r0,[EMAIL PROTECTED] 0000002C mtspr SRR0,r0 00000030 rfi my questions are: 1. Is the code "kernel = (void (*)(bd_t *, ulong, ulong, ulong, ulong))hdr->ih_ep" branch right? 2. What's the expected code after "kernel = (void (*)(bd_t *, ulong, ulong, ulong, ulong))hdr->ih_ep"? 3. When the kernel run to the "boot/simple/head.s"? thanks a lot poorbeyond 2007-07-22
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