Hi all, I am working with a Xilinx Virtex II Pro evaluation board, wich has two PowerPC 405 and I'm trying to boot a vanilla linux kernel 2.6.23.14. Until now I've manged to make it uncompress the kernel, but it doesn't boot. My question is how the initial execution (the one who uncompresses the kernel image) transfers the processor to the kernel itself. I've looked in the arch/ppc/boot/simple/relocate.S code and it jumps to the position 0x0 after uncompressing, is it right? The kernel is uncompressed at that position?
Thanks, -- Ricardo Ayres Severo <[EMAIL PROTECTED]> _______________________________________________ Linuxppc-embedded mailing list [email protected] https://ozlabs.org/mailman/listinfo/linuxppc-embedded
