This should do it, I think (it's a fairly simple task): for i in $(find _source_ -type d); do mkdir "_dest_/$i"; done
On Thu, Apr 16, 2009 at 1:29 AM, Nelson Serafica <[email protected]> wrote: > > I guess there's none. Thanks BTW I'll just create a script instead since > I have no choice > >> write a shell script to do that. >> > > > > -- Daniel --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Linux Users Group. To post a message, send email to [email protected] To unsubscribe, send email to [email protected] For more options, visit our group at http://groups.google.com/group/linuxusersgroup -~----------~----~----~----~------~----~------~--~---
