On 5/28/98 11:44 AM, Mike Nolan <[EMAIL PROTECTED]> wrote...
>Lazlo Nibble wrote:
>>
>> On Thu, May 28, 1998 at 10:23:12AM -0500, Adam Bailey wrote:
>>
>> > Let's say the average email is 5k. I did a random sampling in my AOL
>> > mailbox, and it seemed to work out to that. And let's say we want to
>> > increase that absurdly small 550 to 600, a minor improvement. 50 messages
>> > X 5k = 250k * (12,000,000 members * 1.2 average screen names per members
>> > (1997) = 14,400,000) = 3,525,000,000. That's 3.5 gigabytes for just an
>> > extra 50 5k messages.
>>
>> Wow, a whole $200 worth of disk. I can see why AOL wouldn't want to make
>> that kind of investment. :-)
>
>I think Adam's math skills need a refresher course. -)
>
>250K * 12M * 1.2 = 3,600,000 MILLION bytes, or 3.6 terabytes. Anybody
>willing to sell me that for $200?
Ooops, you're right. I think I counted 250k as 250 bytes when I was doing
the math.
--
Adam Bailey | Chicago, Illinois
-=-=-=-=-=-=-=-=-| "Do not take life too seriously;
[EMAIL PROTECTED] | you will never get out of it alive."
[EMAIL PROTECTED] | - Elbert Hubbard
Finger for PGP | http://www.tezcat.com/~adamb/
