Thanks for the speedy reply....I think this will solve my problem!
Scott
>From: [EMAIL PROTECTED]
>Reply-To: [EMAIL PROTECTED]
>To: [EMAIL PROTECTED]
>Subject: [REBOL] time function Re:
>Date: Mon, 22 Nov 1999 11:03:04 -0500
>
>Hi... There was quite a discussion of this question back at the end of
>October... which then became a discussion of Julian dates. I think this
>was
>the most elegant/simplest answer to your question though.. thanks to
>msg#43926 from Thomas Jensen:
>
>epoch: func [] [
> x: (* now - 1-1-1970 86400) + now/time ; returns a time! value
> x/3 + ((x/1 * 60) + x/2 * 60) ; converts to seconds, would be
>nice
> ; if (to integer! x) worked...
> ]
>
>Russ
>-------------------------------------
>At 09:30 AM 11/22/99 +0000, you wrote:
> >Hello everyone....forgive a newbie question....Perl has a time function
> >which returns a number of seconds since a certain date. With Rebol I can
>get
> >now/time, now/date, etc. Is there an easy way to get the same type of
>value
> >that the Perl time() function returns? I seem to have problems
>multiplying
> >what returns from now with integer or decimal data types, like in a
>payroll
> >calculation where hours_worked * pay_rate = paycheck. Thanks in advance
>for
> >your help.
> >
> >Rebol rules!
> >
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