The template for the function call would be:
f/ref1/ref2 <a> <arg1> <arg2>
So, try:
>> f: func [ a /ref1 arg1 /ref2 arg2] [ either ref2 [ print "ref2" ] [
print "no ref2" ] ]
>> f/ref1/ref2 3 4 1
ref2
- Michael Jelinek
[EMAIL PROTECTED] on 08/28/2000 09:43:06 AM
From: [EMAIL PROTECTED] on 08/28/2000 09:43 AM
Please respond to [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
cc:
Subject: [REBOL] what if a function requires multiple argument-based
refinements?
This is a bit of an abstract question by a person who is 1/3rd of the way
through the McGraw text, but I just keep popping with questions.
What if I had the following:
>> f: func [ a /ref1 arg1 /ref2 arg2] [ either ref2 [ print "ref2" ] [
print "no ref2" ] ]
>> f/ref1 3 /ref2 4 1
no ref2
== 1
>>
how could I call the function "f" to make use of both refinements?
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