Hi, Like this: f/ref1/ref2 3 4 1 Hope that's what you want... Anton. [EMAIL PROTECTED] wrote: > This is a bit of an abstract question by a person who is 1/3rd of the way through >the McGraw text, but I just keep popping with questions. > > What if I had the following: > > >> f: func [ a /ref1 arg1 /ref2 arg2] [ either ref2 [ print "ref2" ] [ print "no >ref2" ] ] > >> f/ref1 3 /ref2 4 1 > no ref2 > == 1 > >> > > how could I call the function "f" to make use of both refinements? > > Get your FREE Email and Voicemail at Lycos Communications at > http://comm.lycos.com
