Hi Phil

Don't know about most efficient, but this is probably close:

    foreach item reduce [v2 v3][append v1 item]

HTH
-Larry

----- Original Message ----- 
From: [EMAIL PROTECTED] 
To: [EMAIL PROTECTED] 
Sent: Tuesday, October 10, 2000 5:48 PM
Subject: [REBOL] Efficient binary functions


Suggestions !!!
 
v1: #{01}
v2: #{03}
v3: #{44}
 
What's the most efficient way of concatenating v1, v2 and v3
 
Obviously.I can use:
 
append v1 v2
append v1 v3
 
However, if I have X vars to concatenate this is unwieldy.
 
Phil Hayes
 
 

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