Hi Phil
Don't know about most efficient, but this is probably close:
foreach item reduce [v2 v3][append v1 item]
HTH
-Larry
----- Original Message -----
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, October 10, 2000 5:48 PM
Subject: [REBOL] Efficient binary functions
Suggestions !!!
v1: #{01}
v2: #{03}
v3: #{44}
What's the most efficient way of concatenating v1, v2 and v3
Obviously.I can use:
append v1 v2
append v1 v3
However, if I have X vars to concatenate this is unwieldy.
Phil Hayes