> Can someone tell me what makes this fail?
>
> >> a: { one two
> { three four }
> == " one two^/ three four "
> >> a2: trim/auto copy a
> == "one two^/ three four "
This I cannot explain. It doesn't look right at all. However if you define
the source string differently it works:
trim/auto copy rejoin [" one two" newline " three four " ]
== "one two^/three four "
> >> a3: trim/with "^/" copy a2
> == ""
You got your parameters in the wrong order. Should be:
>> a3: trim/with copy a2 "^/"
== "one two three four "
> or this?
>
> ""
> >> a3: trim/all copy a2
> == "onetwothreefour"
Is correct
> >> a4: trim/with "two" copy a3
> == ""
Again, the order of your parameters is wrong. Do this instead:
>> a4: trim/with copy a3 "two"
== "nehreefur"
> I thought the "TRIM/WITH" command removes the supplied string value and
> returns the rest of the string. I tried out the examples in the new core
> manual, page 235.
No. Trim/with interprets the supplied string value as a set of characters
that must be removed from the source string. It does not remove sub-strings.
HTH,
Brett
