You can check if a value is a pointer using:
bool
SBValue::TypeIsPointerType ();
If you are using a more up to date LLDB that ha
value.GetType().IsPointerType();
Then you can check the pointer value to see if you really want to show the
children. We will always return the number of children that a SBValue's type
has even if the value is invalid because you might have expanded a pointer
value before and the UI is remembering a user expansion state. The latest
LLDB's also have a "get value as unsigned" convenience function:
uint64_t
SBValue::GetValueAsUnsigned(uint64_t fail_value=0);
so you could do something like:
if (value.TypeIsPointerType() && value.GetValueAsUnsigned() == 0)
{
// NULL pointer....
}
else
{
}
On Nov 22, 2011, at 2:34 PM, Andrey Zaytsev wrote:
> Hi!
> I'm always getting this error when trying to expand children of NULL pointer.
> But SBValue::GetChildrenCount() doesn't return zero.
> It produces some trouble in our frontend: we are trying to be lazy and not
> discover value's children when it's not needed by user explicitly but we
> indicate that children are present since GetChildrenCount() != 0. Any
> workaround maybe?
>
> Andrey Zaytsev
> Software Developer at JetBrains, Inc
> http://jetbrains.com
> Develop with pleasure!
>
>
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