$ ./lldb /bin/ls
Current executable set to '/bin/ls' (x86_64).
(lldb) b malloc
Breakpoint 1: 2 locations.
(lldb) r
Process 48448 launched: '/bin/ls' (x86_64)
Process 48448 stopped
* thread #1: tid = 0x58fee, 0x00007fff906cd8f9 libsystem_malloc.dylib`malloc,
stop reason = breakpoint 1.2
frame #0: 0x00007fff906cd8f9 libsystem_malloc.dylib`malloc
libsystem_malloc.dylib`malloc:
-> 0x7fff906cd8f9: pushq %rbp
0x7fff906cd8fa: movq %rsp, %rbp
0x7fff906cd8fd: pushq %rbx
0x7fff906cd8fe: pushq %rax
(lldb) r
There is a running process, kill it and restart?: [Y/n] <— this is where you
are hung waiting for input
You probably want to say i.HandleCommand(“c”,res)
OTOH, I wonder if we could do any better w.r.t. handling commands that require
input - I think in our test suite, to do that kind of thing, we use pexpect to
read/write from/to LLDB’s stdin/stdout
And with all of that said, if you are trying to do any serious instrumentation
of your process, you might want to consider using the LLDB event model instead
of HandleCommand() scripting.
An example of how you would do that in Python is in our source base at
examples/python/process_events.py and (for the C++ way) in the lldb-perf project
Enrico Granata
📩 egranata@.com
☎️ 27683
On Jun 26, 2013, at 1:57 PM, Langmuir, Ben <[email protected]> wrote:
> I’m trying to use the ‘run’ command from the python API when my process has
> stopped at a breakpoint, but it appears to hang. Script attached.
>
> i.HandleCommand('b main', res)
> i.HandleCommand('r', res) -> runs to breakpoint correctly
> i.HandleCommand('r', res) -> appears to hang
>
> This seems like a bug, but I thought I would ask in case the interpreter was
> waiting for some kind of input I wasn’t providing… I’m running on Linux, and
> haven’t had a chance to try OS X yet.
>
> Ben
> <test.py>_______________________________________________
> lldb-dev mailing list
> [email protected]
> http://lists.cs.uiuc.edu/mailman/listinfo/lldb-dev
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