On 12 September 2014 12:59, Zachary Turner <ztur...@google.com> wrote:
> The important thing seems to be whether glibc implies linux, not the other
> way around.

It doesn't -- Debian k/FreeBSD has __GLIBC__ and __FreeBSD_kernel__,
and not __linux__.

> The issue is that all of our CMake decisions are based on OS platform.  If I
> want to conditionally compile an entire file based on one of these
> conditions, I need to translate it into something that fits well into the
> CMake build.

That should be fine, although in some cases there won't be a mapping
to a single OS if multiple macros are used.

An OS to macro map would include, for example:

FreeBSD: __FreeBSD__, __FreeBSD_kernel__
Linux distros: __linux__, __GLIBC__
kFreeBSD: __GLIBC__, __FreeBSD_kernel__

The kFreeBSD project needs to use the FreeBSD kernel's debugging
interface (e.g., the ptrace syscall and constants) and glibc's
userland interfaces (e.g., setting thread names).
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