If I remove REG_ENHANCED and compile/run I get "No match" =(
On Tue, Jan 20, 2015 at 3:50 PM, Zachary Turner <ztur...@google.com> wrote:
> Linus doesn't appear to have REG_ENHANCED.
>
> On Tue, Jan 20, 2015 at 3:37 PM, Greg Clayton <gclay...@apple.com> wrote:
>
>> The code below fails to match the string "a" to the regex "^a$" on MacOSX
>> if both "REG_EXTENDED | REG_ENHANCED" are specified, but it will pass if
>> just REG_ENHANCED is used.
>>
>> Can someone run this on linux to see if the code below fails as well on
>> linux? I want to make sure it isn't just an old version of regex we have in
>> our libc...
>>
>>
>>
>> #include <stdio.h>
>> #include <stdint.h>
>> #include <regex.h>
>>
>> #define DEFAULT_REG_FLAGS (REG_EXTENDED | REG_ENHANCED)
>>
>> int main (int argc, char const *argv[], char const *envp[])
>> {
>> regex_t re;
>> const char *regex_input = "a";
>> int err = regcomp (&re, "^a$", DEFAULT_REG_FLAGS);
>> if (err == 0)
>> {
>> err = regexec (&re, regex_input, 0, NULL, DEFAULT_REG_FLAGS);
>> if (err == 0)
>> {
>> puts("matched");
>> }
>> else
>> {
>> char error_str[2048];
>> const size_t actual_error_str_size = regerror(err, &re,
>> error_str, sizeof(error_str));
>> puts(error_str);
>> }
>> }
>> return 0;
>> }
>>
>>
>>
>>
>>
>>
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>>
>
>
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