================
@@ -2333,6 +2352,170 @@ DwarfDebug::emitInitialLocDirective(const 
MachineFunction &MF, unsigned CUID) {
   return PrologEndLoc;
 }
 
+void DwarfDebug::findKeyInstructions(const MachineFunction *MF) {
+  // New function - reset KeyInstructions.
+  KeyInstructions.clear();
+
+  // The current candidate is_stmt instructions for each source atom.
+  // Map {(InlinedAt, Group): (Rank, Instructions)}.
+  DenseMap<std::pair<DILocation *, uint32_t>,
+           std::pair<uint16_t, SmallVector<const MachineInstr *>>>
+      GroupCandidates;
+
+  // For each instruction:
+  //   * Skip insts without DebugLoc, AtomGroup or AtomRank, and line zeros.
+  //   * Check if insts in this group have been seen already in 
GroupCandidates.
+  //     * If this instr rank is equal, add this instruction to 
KeyInstructions.
+  //       Remove existing instructions from KeyInstructions if they have the
+  //       same parent.
+  //     * If this instr rank is higher (lower precedence), ignore it.
+  //     * If this instr rank is lower (higher precedence), erase existing
+  //       instructions from KeyInstructions. Add this instr to 
KeyInstructions.
+
+  for (auto &MBB : *MF) {
+    // Rather than apply is_stmt directly to Key Instructions, we "float"
+    // is_stmt up to the 1st instruction with the same line number in a
+    // contiguous block. That instruction is called the "buoy". The
+    // buoy gets reset if we encouner an instruction with an atom
+    // group.
+    const MachineInstr *Buoy = nullptr;
+    // The atom group number associated with Buoy which may be 0 if we haven't
+    // encountered an atom group yet in this blob of instructions with the same
+    // line number.
+    uint64_t BuoyAtom = 0;
+
+    for (auto &MI : MBB) {
+      if (MI.isMetaInstruction())
+        continue;
+
+      if (!MI.getDebugLoc() || !MI.getDebugLoc().getLine())
+        continue;
+
+      // Reset the Buoy to this instruciton if it has a different line number.
+      if (!Buoy ||
+          Buoy->getDebugLoc().getLine() != MI.getDebugLoc().getLine()) {
+        Buoy = &MI;
+        BuoyAtom = 0;
+      }
+
+      // Call instructions are handled specially - we always mark them as key
+      // regardless of atom info.
+      const auto &TII =
+          *MI.getParent()->getParent()->getSubtarget().getInstrInfo();
+      if (MI.isCall() || TII.isTailCall(MI)) {
+        assert(MI.getDebugLoc() && "Unexpectedly missing DL");
+
+        // Calls are always key.
+        KeyInstructions.insert(Buoy);
+
+        uint64_t Group = MI.getDebugLoc()->getAtomGroup();
+        uint8_t Rank = MI.getDebugLoc()->getAtomRank();
+        if (Group && Rank) {
+          auto *InlinedAt = MI.getDebugLoc()->getInlinedAt();
+          auto &[CandidateRank, CandidateInsts] = GroupCandidates[{InlinedAt, 
Group}];
+
+          // This looks similar to the non-call handling code, except that
+          // we don't put the call into CandidateInsts so that they can't be
+          // made un-key. As a result, we also have to take special care not
+          // to erase the is_stmt from the buoy, and prevent that happening
+          // in the future.
+
+          if (CandidateRank == Rank) {
+            // We've seen other instructions in this group of this rank. 
Discard
+            // ones we've seen in this block, keep the others.
+            assert(!CandidateInsts.empty());
+            SmallVector<const MachineInstr *> Insts;
+            Insts.reserve(CandidateInsts.size());
+            for (auto &PrevInst : CandidateInsts) {
+              if (PrevInst->getParent() != MI.getParent())
+                Insts.push_back(PrevInst);
+              else if (PrevInst != Buoy)
+                KeyInstructions.erase(PrevInst);
+            }
+
+            if (Insts.empty()) {
+              CandidateInsts.clear();
+              CandidateRank = 0;
+            } else {
+              CandidateInsts = std::move(Insts);
+            }
+
+          } else if (CandidateRank > Rank) {
+            // We've seen other instructions in this group of lower precedence
+            // (higher rank). Discard them.
+            for (auto *Supplanted : CandidateInsts) {
+              // Don't erase the is_stmt we're using for this call.
+              if (Supplanted != Buoy)
+                KeyInstructions.erase(Supplanted);
+            }
+            CandidateInsts.clear();
+            CandidateRank = 0;
+          }
+        }
+
+        // Avoid floating any future is_stmts up to the call.
+        Buoy = nullptr;
+        continue;
+      }
+
+      auto *InlinedAt = MI.getDebugLoc()->getInlinedAt();
+      uint64_t Group = MI.getDebugLoc()->getAtomGroup();
+      uint8_t Rank = MI.getDebugLoc()->getAtomRank();
+      if (!Group || !Rank)
+        continue;
+
+      // Don't let is_stmts float past instructions from different source 
atoms.
+      if (BuoyAtom && BuoyAtom != Group) {
+        Buoy = &MI;
+        BuoyAtom = MI.getDebugLoc()->getAtomGroup();
+      }
+
+      auto &[CandidateRank, CandidateInsts] = GroupCandidates[{InlinedAt, 
Group}];
+
+      if (CandidateRank == 0) {
+        // This is the first time we're seeing an instruction in this atom
+        // group. Add it to the map.
+        assert(CandidateInsts.empty());
+        CandidateRank = Rank;
+        CandidateInsts.push_back(Buoy);
+
+      } else if (CandidateRank == Rank) {
+        // We've seen other instructions in this group of this rank. Discard
+        // ones we've seen in this block, keep the others, add this one.
+        assert(!CandidateInsts.empty());
+        SmallVector<const MachineInstr *> Insts;
+        Insts.reserve(CandidateInsts.size() + 1);
+        for (auto &PrevInst : CandidateInsts) {
+          if (PrevInst->getParent() != MI.getParent())
+            Insts.push_back(PrevInst);
+          else
+            KeyInstructions.erase(PrevInst);
+        }
+        Insts.push_back(Buoy);
+        CandidateInsts = std::move(Insts);
----------------
jmorse wrote:

An alternative perhaps: only permit zero or one `MachineInstr`s from a block in 
CandidateInsts, checked by an EXPENSIVE_CHECKS check. Then we either:
 * If there are zero instructions present from the same block, append the new 
one,
 * If there's one instruction present from the same block, overwrite it,

Hopefully avoiding there ever being more than one instruction from the same 
block? Unless they can enter via some other route.

https://github.com/llvm/llvm-project/pull/133495
_______________________________________________
llvm-branch-commits mailing list
llvm-branch-commits@lists.llvm.org
https://lists.llvm.org/cgi-bin/mailman/listinfo/llvm-branch-commits

Reply via email to