http://llvm.org/bugs/show_bug.cgi?id=19425
Bug ID: 19425
Summary: ostream_iterator::operator* is not constant
Product: libc++
Version: 3.4
Hardware: All
OS: All
Status: NEW
Severity: normal
Priority: P
Component: All Bugs
Assignee: [email protected]
Reporter: [email protected]
CC: [email protected], [email protected]
Classification: Unclassified
There is a trick used in ostream_iterator, that doesn't quite conform to
standard.
ostream_iterator<T>::operator* returns itself instead of something with
operator=(const T &);
It's almost never an issue since the all the stl algorithms do * and ++ at the
same time. But if we separate * and ++ the way that is shown below, the program
won't compile.
---------
#include <iostream>
#include <iterator>
using namespace std;
void write_5(const ostream_iterator<int> &i)
{
*i = 5;
}
int main()
{
ostream_iterator<int> i(cout);
write_5(i);
++i;
}
---------
I believe ostream_iterato<T>::operator* must be defined as const and return a
temporary object, that holds the reference to the stream and have operator=
that do the job. In any case, the code above conforms to standard and doesn't
compile.
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