We can add this as the first line as an optimization:
if( this == rObject) { return true; }
right! I'll add this now.
Also, will the hashCode based on the timestamp be enough to be consistent with equals?
Yes. The general contact for the hashcode method says:
1 Two equal objects must have the same hashcode. 2 Two unequal objects can have the same hashcode.
Item 1 does *not* mean that unequal objects must have different hashcodes, which is actually impossible to achieve.
Does this answer the question?
cheers,
Paul
-- Ceki Gülcü
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