Howdy,
try {
String a = null;
System.out.println(a.length());
} catch (Exception e) {
logger.error("Error printing string: ", e);
}
Note the comma, i.e. the error(Object, Throwable) version of the API.
All the levels (logger.info(...), logger.warn(...), etc) have a version
of their signature with a Throwable argument.
Yoav Shapira
Millennium ChemInformatics
>-----Original Message-----
>From: Andreas Bothner [ MTN - Innovation Centre ]
>[mailto:[EMAIL PROTECTED]
>Sent: Friday, August 29, 2003 9:55 AM
>To: Log4J Users List
>Subject: how do I log an exception stacktrace
>
>Hi,
>
>I apologize if this is a stupid question, but how would I log out an
>exception's stacktrace using logger.debug() ?
>
>Regards,
>Andreas Bothner
>Systems Integrator
>
>
>NOTE: This e-mail message is subject to the MTN Group disclaimer see
>http://www.mtn.co.za/email_disclaimer.asp
>
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