Hello,
The definition of ltp_clone looks like this:
int
ltp_clone(unsigned long clone_flags, int (*fn)(void *arg), void *arg,
size_t stack_size, void *stack)
{
int ret;
#if defined(__hppa__)
ret = clone(fn, stack, clone_flags, arg);
#elif defined(__ia64__)
ret = clone2(fn, stack, stack_size, clone_flags, arg, NULL, NULL, NULL);
#elif defined(__arm__)
/*
* Stack size should be a multiple of 32 bit words
* & stack limit must be aligned to a 32 bit boundary
*/
ret = clone(fn, (stack ? stack + stack_size : NULL),
clone_flags, arg);
#else
ret = clone(fn, (stack ? stack + stack_size - 1 : NULL),
clone_flags, arg);
#endif
return ret;
}
I believe the __arm__ case is to ensure that we pass an aligned
stack pointer to the syscall (as required by the architecture).
What I don't understand, is why we pass an unaligned address in
the #else case? Given that a stack push decrements the sp before
writing on every architecture I know of, it seems that the __arm__
case should be used as the default rather than forcing a misaligned
stack on other architectures.
Will
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