Function output can be canceled by pthread_cancel(), which, maybe, leads to a deadlock as it calls pthread_mutex_lock(). That's catched in case "pthread_join/4-1.c".
So,disable thread cancelability until output finishes. Signed-off-by: LIDAN<[email protected]> --- .../conformance/interfaces/testfrmw/testfrmw.c | 4 ++++ 1 files changed, 4 insertions(+), 0 deletions(-) diff --git a/testcases/open_posix_testsuite/conformance/interfaces/testfrmw/testfrmw.c b/testcases/open_posix_testsuite/conformance/interfaces/testfrmw/testfrmw.c index 034faa9..fb54ee9 100644 --- a/testcases/open_posix_testsuite/conformance/interfaces/testfrmw/testfrmw.c +++ b/testcases/open_posix_testsuite/conformance/interfaces/testfrmw/testfrmw.c @@ -28,6 +28,7 @@ #include <time.h> #include <sys/types.h> +#include <pthread.h> /* We use a mutex to avoid conflicts in traces */ static pthread_mutex_t m_trace = PTHREAD_MUTEX_INITIALIZER; @@ -43,7 +44,9 @@ void output(char *string, ...) char *ts = "[??:??:??]"; struct tm *now; time_t nw; + int oldstate; + pthread_setcancelstate(PTHREAD_CANCEL_DISABLE,&oldstate); pthread_mutex_lock(&m_trace); nw = time(NULL); now = localtime(&nw); @@ -56,6 +59,7 @@ void output(char *string, ...) vprintf(string, ap); va_end(ap); pthread_mutex_unlock(&m_trace); + pthread_setcancelstate(oldstate,NULL); } void output_fini(void) -- 1.7.1 ------------------------------------------------------------------------------ This SF email is sponsosred by: Try Windows Azure free for 90 days Click Here http://p.sf.net/sfu/sfd2d-msazure _______________________________________________ Ltp-list mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/ltp-list
