Hi!
> Sorry, but is it possible to use #ifdef or #if inside a #define macro?
Right it does not, sorry. I tend to forget how dumb it the C preprocessor is.
> This doesn't work:
>
> #define MYDEF(NN) \
> # ifdef TST_USE_COMPAT16_SYSCALL
> return NN(0);
> # else
> return NN(1);
> # endif
>
> MYDEF(bla)
We need to pull the first if out of the macro and we can do the second
one as a regular if (it will be optimized away anyway).
#ifdef TST_USE_COMPAT16_SYSCALL
# define LTP_CREATE_SYSCALL(sys_name, ...) \
if (__NR_##sys_name##32 != __LTP__NR_INVALID_SYSCALL) { \
return ltp_syscall(sys_name, ##__VA_ARGS__); \
} else { \
errno = ENOSYS; \
return -1; \
}
#else
# define LTP_CREATE_SYSCALL(sys_name, ...) \
return sys_name(__VA_ARGS__)
#endif
The usage will be:
int SETGROUPS(size_t size, const GID_T *list)
{
LTP_CREATE_SYSCALL(getgroups, size, list);
}
Does this sound reasonable?
--
Cyril Hrubis
[email protected]
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