Hi!
On 11/11/2014 05:45 PM, Cyril Hrubis wrote:
> Hi!
>> -void *thread_fn(void *val)
>> +static int load_cpu(int max_freq_khz)
>>   {
>> -    struct timeval tv_start;
>> -    struct timeval tv_end;
>> -    int i, res = 0;
>> -    intptr_t timeout = (intptr_t) val;
>> -
>> -    gettimeofday(&tv_start, NULL);
>> -    tst_resm(TINFO, "load CPU0 for %ld sec...", timeout);
>> +    int sum = 0, i = 0, total_time_ms;
>> +    struct timespec tv_start, tv_end;
>>   
>> -    do {
>> -            for (i = 1; i < 10000; ++i)
>> -                    res += i * i;
>> -            gettimeofday(&tv_end, NULL);
>> -            sched_yield();
>> -    } while ((tv_end.tv_sec - tv_start.tv_sec) < timeout);
>> -
>> -    tst_resm(TINFO, "CPU0 load done: insignificant value '%d'", res);
>> +    const int max_sum = max_freq_khz / 1000;
>> +    const int units = 1000000; /* Mhz */
>>   
>> -    return NULL;
>> -}
>> +    clock_gettime(CLOCK_MONOTONIC_RAW, &tv_start);
>>   
>> -static int load_cpu(intptr_t timeout)
>> -{
>> -    pthread_t thread_id;
>> +    do {
>> +            for (i = 0; i < units; ++i)
>> +                    asm ("" : : : "memory");
>> +    } while (++sum < max_sum);
>>   
>> -    if (pthread_create(&thread_id, 0, thread_fn,
>> -            (void *) timeout) != 0) {
>> -            tst_brkm(TBROK | TERRNO, cleanup,
>> -                    "pthread_create failed at %s:%d",
>> -                    __FILE__, __LINE__);
>> -    }
>> +    clock_gettime(CLOCK_MONOTONIC_RAW, &tv_end);
>>   
>> -    sleep(2 * timeout / 3);
>> +    total_time_ms = (tv_end.tv_sec - tv_start.tv_sec) * 1000 +
>> +            (tv_end.tv_nsec - tv_start.tv_nsec) / 1000000;
>>   
>> -    int cur_freq;
>> -    SAFE_FILE_SCANF(cleanup, curspeed, "%d", &cur_freq);
>> -    tst_resm(TINFO, "got cpu freq under load: %d", cur_freq);
>> +    if (!total_time_ms)
>> +            tst_brkm(TBROK, cleanup, "can't calc freq, time period is 0");
>>   
>> -    pthread_join(thread_id, NULL);
>> +    tst_resm(TINFO, "elapsed time is %d ms", total_time_ms);
>>   
>> -    return cur_freq;
>> +    return sum * 1000 / total_time_ms;
> Is this conversion really necessary? I guess that we can also return
> the elapsed time here and test that the time is shorted by a few
> percents with boost enabled in the test_run() function.

I guess not really necessary as sum is a constant, just wanted to keep 
the function returning frequency which is more interesting result then 
time spent. OK, I'll change it to return total_time_ms.

>
> Otherwise it looks good.


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