Hello, I'm, trying to build ust-0.15 under Centos6.0 (kernel 2.6.32.71, gcc 4.4.4)
The ./configure stage is OK. Attached config.log The attached build_ust.sh is the script used to run ./configure But when I ran "make" I got: [zvivered@localhost ust-0.15]$ make make all-recursive make[1]: Entering directory `/home/zvivered/GNU/ust-0.15' Making all in snprintf make[2]: Entering directory `/home/zvivered/GNU/ust-0.15/snprintf' make[2]: Nothing to be done for `all'. make[2]: Leaving directory `/home/zvivered/GNU/ust-0.15/snprintf' Making all in libustcomm make[2]: Entering directory `/home/zvivered/GNU/ust-0.15/libustcomm' CC libustcomm_la-ustcomm.lo CCLD libustcomm.la make[2]: Leaving directory `/home/zvivered/GNU/ust-0.15/libustcomm' Making all in libustctl make[2]: Entering directory `/home/zvivered/GNU/ust-0.15/libustctl' CC libustctl_la-libustctl.lo CCLD libustctl.la /usr/bin/ld: libustctl.so.0: No such file: No such file or directory collect2: ld returned 1 exit status make[2]: *** [libustctl.la] Error 1 make[2]: Leaving directory `/home/zvivered/GNU/ust-0.15/libustctl' make[1]: *** [all-recursive] Error 1 make[1]: Leaving directory `/home/zvivered/GNU/ust-0.15' make: *** [all] Error 2 It seems make looks for libustctl.so.0 But in this stage, libustctl.so.0 was not created. It is created only after "make install" when I added --disable-shared, I made some progress. Is it a wise step ? Thanks, Zvika.
config.log
Description: Binary data
build_ust.sh
Description: Bourne shell script
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