On 24 December 2013 12:22, Alexander Gladysh <aglad...@gmail.com> wrote:
> On Tue, Dec 24, 2013 at 5:39 AM, Hisham <h...@hisham.hm> wrote:
>> On 23 December 2013 20:22, Alexander Gladysh <aglad...@gmail.com> wrote:
>>> On Tue, Dec 24, 2013 at 2:01 AM, Alexander Gladysh <aglad...@gmail.com>
>>> wrote:
>>>> On Tue, Dec 24, 2013 at 1:34 AM, Alexander Gladysh <aglad...@gmail.com>
>>>> wrote:
>>>
>>>>> $ luarocks list | grep '^[^ ]' | tail -n +4 | xargs -n1 luarocks show
>>>>> | grep code.exports
>>>>>
>>>>> This command takes five seconds to execute on my box with 74 rocks
>>>>> installed. This is way to slow for my tool. :-(
>>>>
>>>> To compare, this hack takes 0.2s:
>>>>
>>>> $ (cd `luarocks path | grep LUA_PATH | cut -d "'" -f 2- | cut -d "?"
>>>> -f 1` && find . -wholename '*code/exports.lua' | cut -c 3-)
>>>
>>> 2.1.1 with porcelain is just as slow...
>>
>> The fastest method, I think, would be to scan the manifest file:
>>
>> lua -e "dofile('/your/lib/luarocks/rocks/manifest'); for k,_ in
>> pairs(modules) do if k:match("code.exports") then print(k) end end"
>
> Thanks. Is there a standard way to get the default path to the file?
I'm afraid not... That depends on where your repositories are, based
on your configuration. There are currently no commands to inspect this
info from the outside.
>>> $ luarocks list --porcelain | cut -f 1 | xargs -n1 luarocks show
>>> --modules | xargs -n1 | grep code.exports
>>>
>>> BTW, is there a reason why `luarocks show --modules' doesn't print a
>>> module per line?
>>
>> I don't know. I wasn't the one who coded it.
>
> But you're the maintainer.
>
> https://github.com/keplerproject/luarocks/issues/210
Sure. I can add the newlines, I just hope I don't break anybody's code
doing that...
-- Hisham
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