Re: Query: A ? B

[Erik Hatcher]

Actually a slop of 1 does guarantee order... it is either an exact 
match or 1 term off.  It takes a slop of 2 or greater for reverse order 
matches.

But it is not exactly 1 term off, which is what Jochen wants.  *shrug*

	Erik

On Mar 4, 2004, at 6:22 PM, Otis Gospodnetic wrote:

Ah, sorry, I had misread your email, thinking you were asking a way to
match a single character.
The only thing that comes to my tired mind now is a phrase query with a
slop of 1, but that doesn't gurantee order, I believe.
Otis

--- Jochen Frey <[EMAIL PROTECTED]> wrote:
Otis:

Maybe I don't understand this right, but I *think* I am looking for
something different:
I am trying to write a query like this: "my * house" which should
match "my
own house", "my red house", "my small house", but should not match
"my
house" ... you get the idea.
If I am not mistaken, a wildcard query only works if the wildcard is
within
a word (or token), and it would allow me to do things like "g*"
matching
"green", "great", ...etc. I don't know how to make that work for
multi words
scenarios.
Here is what I tried WildcardQuery in the unit test (TestBasics):

Query query = new WildcardQuery(new Term("field","six hundred *
five"));
Thanks!
Jochen
-----Original Message-----
From: Otis Gospodnetic [mailto:[EMAIL PROTECTED]
Sent: Thursday, March 04, 2004 12:00 PM
To: Lucene Users List
Subject: Re: Query: A ? B
Use WildcardQuery: A?B

Otis

--- Jochen Frey <[EMAIL PROTECTED]> wrote:
Hi Everyone.

I am trying to figure out how create a query that matches

A ? B

Where ? is exactly one token. Can anyone tell me how to do that?

Obviously it's easy to match 'A * B' where '*' is 0 or 1 tokens
(just
use a
PhraseQuery and set slop to 1). However, if I require exactly one
word/token
between 'A' and 'B'?
BTW, I know a very clumsy way of doing this, but I really don't
like
it: For
each indexed token insert a token (for example 'X') at the same
token-position. Then the query would be: "A X B" and everybody
(except the
indexing performance as well as the size on disk) would be happy.
There's got to be an easier way. Right?

Thanks in advance!
Jochen


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