Sadly, I am still running into problems
Explain shows the following after the modification.
Rank: 1 ID: 11285358 Score: 5.5740864E8
5.5740864E8 = product of:
8.3611296E8 = sum of:
8.3611296E8 = product of:
6.6889037E9 = weight(title:iron in 1235940), product of:
0.12621856 = queryWeight(title:iron), product of:
7.0507255 = idf(docFreq=10816)
0.017901499 = queryNorm
5.2994613E10 = fieldWeight(title:iron in 1235940), product of:
1.0 = tf(termFreq(title:iron)=1)
7.0507255 = idf(docFreq=10816)
7.5161928E9 = fieldNorm(field=title, doc=1235940)
0.125 = coord(1/8)
2.7106019E-8 = product of:
1.08424075E-7 = sum of:
5.7318403E-9 = weight(abstract:an in 1235940), product of:
0.03711049 = queryWeight(abstract:an), product of:
2.073038 = idf(docFreq=1569960)
0.017901499 = queryNorm
1.5445337E-7 = fieldWeight(abstract:an in 1235940), product of:
1.0 = tf(termFreq(abstract:an)=1)
2.073038 = idf(docFreq=1569960)
7.4505806E-8 = fieldNorm(field=abstract, doc=1235940)
1.0269223E-7 = weight(abstract:iron in 1235940), product of:
0.111071706 = queryWeight(abstract:iron), product of:
6.2046037 = idf(docFreq=25209)
0.017901499 = queryNorm
9.24558E-7 = fieldWeight(abstract:iron in 1235940), product of:
2.0 = tf(termFreq(abstract:iron)=4)
6.2046037 = idf(docFreq=25209)
7.4505806E-8 = fieldNorm(field=abstract, doc=1235940)
0.25 = coord(2/8)
0.6666667 = coord(2/3)
Rank: 2 ID: 8157438 Score: 2.7870432E8
2.7870432E8 = product of:
8.3611296E8 = product of:
6.6889037E9 = weight(title:iron in 159395), product of:
0.12621856 = queryWeight(title:iron), product of:
7.0507255 = idf(docFreq=10816)
0.017901499 = queryNorm
5.2994613E10 = fieldWeight(title:iron in 159395), product of:
1.0 = tf(termFreq(title:iron)=1)
7.0507255 = idf(docFreq=10816)
7.5161928E9 = fieldNorm(field=title, doc=159395)
0.125 = coord(1/8)
0.33333334 = coord(1/3)
Rank: 3 ID: 10543103 Score: 2.7870432E8
2.7870432E8 = product of:
8.3611296E8 = product of:
6.6889037E9 = weight(title:iron in 553967), product of:
0.12621856 = queryWeight(title:iron), product of:
7.0507255 = idf(docFreq=10816)
0.017901499 = queryNorm
5.2994613E10 = fieldWeight(title:iron in 553967), product of:
1.0 = tf(termFreq(title:iron)=1)
7.0507255 = idf(docFreq=10816)
7.5161928E9 = fieldNorm(field=title, doc=553967)
0.125 = coord(1/8)
0.33333334 = coord(1/3)
Rank: 4 ID: 8753559 Score: 2.7870432E8
2.7870432E8 = product of:
8.3611296E8 = product of:
6.6889037E9 = weight(title:iron in 2563152), product of:
0.12621856 = queryWeight(title:iron), product of:
7.0507255 = idf(docFreq=10816)
0.017901499 = queryNorm
5.2994613E10 = fieldWeight(title:iron in 2563152), product of:
1.0 = tf(termFreq(title:iron)=1)
7.0507255 = idf(docFreq=10816)
7.5161928E9 = fieldNorm(field=title, doc=2563152)
0.125 = coord(1/8)
0.33333334 = coord(1/3)
I would like to get rid of all normalizations and just have TF and IDF.
What am I missing?
On Thu, 15 Jul 2004 Anson Lau wrote :
>If you don't mind hacking the source:
>
>In Hits.java
>
>In method "getMoreDocs()"
>
>
>
> // Comment out the following
> //float scoreNorm = 1.0f;
> //if (length > 0 && scoreDocs[0].score > 1.0f) {
> // scoreNorm = 1.0f / scoreDocs[0].score;
> //}
>
> // And just set scoreNorm to 1.
> int scoreNorm = 1;
>
>
>I don't know if u can do it without going to the src.
>
>Anson
>
>
>-----Original Message-----
> From: Jones G [mailto:[EMAIL PROTECTED]
>Sent: Thursday, July 15, 2004 6:52 AM
>To: [EMAIL PROTECTED]
>Subject: Scoring without normalization!
>
>How do I remove document normalization from scoring in Lucene? I just want
>to stick to TF IDF.
>
>Thanks.
>
>
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