Thanks for this David. I am pretty farmiliar with rsync which is why I
think I need to use another command to move the copied ones by name/id <
$x and then rsync the folder - more like a find type command
Thanks
Piers
On 27/11/22 19:05, David via luv-main wrote:
On Sun, 27 Nov 2022 at 18:21, Piers Rowan via luv-main
<[email protected]> wrote:
One of my clients has a storage pattern of:
$number.$extension
So it looks like this:
1.pdf
2.pdf
3.csv.
4.jpg
.
$n.$ext
(Where $n is a fairly large number). There was a job running that didn't
complete and I want to rsync only the files that they haven't got
already. Something like:
# not an actual command
rsync /data/999999+.* user@host:/new_folder
Any ideas would be very helpful.
Hi Piers
Although it has many options, one fundamental aspect of rsync
is that by default it is designed to transfer only files (or even
parts of files) that are not already present in the destination.
A quick read of the first couple of paragraphs of 'man rsync' will
confirm this aspect. It's one of the major reasons why people
use it when they do.
Assuming that there are no other files which should be excluded
from the copy process (this aspect is important, but the problem
specification omits that information), I suggest:
rsync -v --dry-run /data/ user@host:/new_folder
The trailing / at the end of /data/ specifies
all files in the directory 'data', which will be
copied into /new_folder
--dry-run means show what would be done, but
don't do anything.
-v will show the names of each file.
If the output of that looks correct, you can remove the
--dry-run.
If there are files that need to be excluded, then a
different approach involving pattern-matching will
be required.
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