codecompl...@free.fr schrieb am 02.09.21 um 16:53:
I'm still learning about lxml, and was wondering if there's a way to get the
tree from the root to avoid writing the file to disk before re-reading it just
for that:
INPUTFILE = "input.kml"
#get rid of NS
with open(INPUTFILE) as reader:
content = reader.read()
content= re.sub('<kml.*?>', '<kml>', content,0, re.DOTALL)
If you really want the namespace declarations stripped out, I'd rather do
it after parsing, not before. (In fact, I would not do it at all, but you
seem to be inclined to do it, for some reason.) Here, you are relying on
specific syntax being used for them, which may or may not be the case in a
given document.
#Read from memory to avoid writing cleaned file to disk and re-read
parser = et.XMLParser(remove_blank_text=True)
root = et.fromstring(bytes(content, encoding='utf8'), parser)
#NameError: name 'tree' is not defined
r = tree.xpath('/Document/name')
print(r[0].tag)
You do not need an ElementTree instance for this. Just use the root element.
I recommend using the find/findall/iterfind() methods over using xpath(),
though. They are faster and support incremental searches. And they simplify
namespace usage.
Stefan
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