Hi,
> I think the logic should be:
> If lxml find one matching child by property name then this is the correct
> answer. If no or more than one child matches not action is taken.
I take it you mean namespace-unqualified property name here?
This is not desirable behavior in my book.
> Matching against the parent namespace is IMHO in no case correct. Matching
> against a default namespace if would be a better option.
Again, I have a different opinion here: Matching against the parent namespace
for child lookup is
exactly the right thing to do (TM). :-)
> > Still, your suggestion for a namespace-free lookup looks like it could be
> > very useful.
Well, you can always do s.th. like
>>> from lxml import etree, objectify
>>> root = objectify.fromstring('<root
>>> xmlns:otherns="/other/namespace"><otherns:x>1</otherns:x><x>2</x></root>')
>>> list(root.iterchildren('{*}x'))
[1, 2]
(works with other iterators too, or you could use XPaths (maybe even compiled)
with local-name())
I must say I'm pretty fundamentally opposed to the suggestion, FWIW.
So -1 from me.
Best,
Holger
Landesbank Baden-Wuerttemberg
Anstalt des oeffentlichen Rechts
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