On 10 Aug 2022, at 9:53, Gilles wrote:
> An important line was missing :-/
>
> no_dups = {}
>
> for row in tree.iter("wpt"):
>
> name,lat,lon = [row.find("name").text] + row.attrib.values()
>
> if name not in no_dups:
>
> no_dups[name] = lat,lon
>
> else:
>
> #dup = remove
>
> row.getparent().remove(row)
Yes, this should work. However, I don't know if adjusting the tree while
looping over it won't the same kind of problems as with other sequences in
Python.
How many elements are there in your tree? Memory use in XML can get very
expensive so combining iterparse with xmlfile would be an alternative. Also, if
you're only interested in duplicate names, use a set rather than a dictionary.
Charlie
--
Charlie Clark
Managing Director
Clark Consulting & Research
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Düsseldorf
D- 40489
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