On 10/03/2026 22:37, Jens Tröger via lxml - The Python XML Toolkit wrote:
>>> xml.xpath("//*[name() = 'w’]") # Any element node whose tag is ‘w’,
ignoring the ns
The comment is not correct and the advice is dodgy: `name()` is the
qualified name, so it's only going to "ignore the ns" for elements which
are specifically not using a namespace prefix:
>>> etree.fromstring('<w
xmlns="http://www.tei-c.org/ns/1.0"/>').xpath('name(/*)')
'w'
>>> etree.fromstring('<t:w
xmlns:t="http://www.tei-c.org/ns/1.0"/>').xpath('name(/*)')
't:w'
If you actually want to ignore the ns, you should use `local-name()`,
that behaves consistently:
>>> etree.fromstring('<t:w
xmlns:t="http://www.tei-c.org/ns/1.0"/>').xpath('local-name(/*)')
'w'
You can use namespace-uri() alongside it:
>>> etree.fromstring('<w
xmlns="http://www.tei-c.org/ns/1.0"/>').xpath('namespace-uri(/*)')
'http://www.tei-c.org/ns/1.0'
>>> etree.fromstring('<t:w
xmlns:t="http://www.tei-c.org/ns/1.0"/>').xpath('namespace-uri(/*)')
'http://www.tei-c.org/ns/1.0'
_______________________________________________
lxml - The Python XML Toolkit mailing list -- [email protected]
To unsubscribe send an email to [email protected]
https://mail.python.org/mailman3//lists/lxml.python.org
Member address: [email protected]
