Michael Koundouros wrote:
> 
> "equation array" was input using the equation array utility (Ctrl-enter)
> "matrix" was input using a 2x3 matrix within a delimiter.
> 
> looking at the ps file you will see the equation in the matrix is rather
> squashed. what I would like is the equation to look like in "equation array"
> but to have the delimiter and numbering of the "matrix" equation.
> 
> Does anyone know how to do this as I was unable to insert a delimiter in
> "equation array".

look at your example.
there are different sizes, used by latex when you have equnarray or
array.

Herbert

-- 
http://www.educat.hu-berlin.de/~voss/lyx/
#LyX 1.1 created this file. For more info see http://www.lyx.org/
\lyxformat 218
\textclass article
\begin_preamble
\usepackage{cite}
\usepackage{fancyhdr}
\lhead{}
\renewcommand {\sectionmark}[1]{\markright{#1}}
\rhead{\nouppercase{\rightmark}}
\end_preamble
\language british
\inputencoding auto
\fontscheme default
\graphics default
\float_placement !hbtp
\paperfontsize default
\spacing single 
\papersize Default
\paperpackage widemarginsa4
\use_geometry 0
\use_amsmath 0
\paperorientation portrait
\secnumdepth 3
\tocdepth 3
\paragraph_separation skip
\defskip medskip
\quotes_language english
\quotes_times 2
\papercolumns 1
\papersides 1
\paperpagestyle fancy

\layout Standard


\begin_inset Formula \begin{eqnarray}
\varphi \left( z_{1}\right)  & = & P\frac{-i}{2\left( s_{1}-s_{2}\right) \left( 
1+is_{1}\right) }\left[ 1-\frac{z_{1}}{\sqrt{z^{2}_{1}-R^{2}\left( 1+s^{2}_{1}\right) 
}}\right] \\
\psi \left( z_{2}\right)  & = & P\frac{+i}{2\left( s_{1}-s_{2}\right) \left( 
1+is_{2}\right) }\left[ 1-\frac{z_{2}}{\sqrt{z^{2}_{2}-R^{2}\left( 1+s^{2}_{2}\right) 
}}\right] \label{equation array} 
\end{eqnarray}

\end_inset 


\layout Standard


\begin_inset Formula \begin{equation}
\label{matrix}
\left. \begin{array}{ccc}
\varphi \left( z_{1}\right)  & = & \displaystyle {P\frac{-i}{2\left( 
s_{1}-s_{2}\right) \left( 1+is_{1}\right) }\left[ 
1-\frac{z_{1}}{\sqrt{z^{2}_{1}-R^{2}\left( 1+s^{2}_{1}\right) }}\right] }\\
\psi \left( z_{2}\right)  & = & \displaystyle {P\frac{+i}{2\left( s_{1}-s_{2}\right) 
\left( 1+is_{2}\right) }\left[ 1-\frac{z_{2}}{\sqrt{z^{2}_{2}-R^{2}\left( 
1+s^{2}_{2}\right) }}\right] }
\end{array}\right\} 
\end{equation}

\end_inset 


\the_end

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