Michael Koundouros wrote: > > "equation array" was input using the equation array utility (Ctrl-enter) > "matrix" was input using a 2x3 matrix within a delimiter. > > looking at the ps file you will see the equation in the matrix is rather > squashed. what I would like is the equation to look like in "equation array" > but to have the delimiter and numbering of the "matrix" equation. > > Does anyone know how to do this as I was unable to insert a delimiter in > "equation array". look at your example. there are different sizes, used by latex when you have equnarray or array. Herbert -- http://www.educat.hu-berlin.de/~voss/lyx/
#LyX 1.1 created this file. For more info see http://www.lyx.org/ \lyxformat 218 \textclass article \begin_preamble \usepackage{cite} \usepackage{fancyhdr} \lhead{} \renewcommand {\sectionmark}[1]{\markright{#1}} \rhead{\nouppercase{\rightmark}} \end_preamble \language british \inputencoding auto \fontscheme default \graphics default \float_placement !hbtp \paperfontsize default \spacing single \papersize Default \paperpackage widemarginsa4 \use_geometry 0 \use_amsmath 0 \paperorientation portrait \secnumdepth 3 \tocdepth 3 \paragraph_separation skip \defskip medskip \quotes_language english \quotes_times 2 \papercolumns 1 \papersides 1 \paperpagestyle fancy \layout Standard \begin_inset Formula \begin{eqnarray} \varphi \left( z_{1}\right) & = & P\frac{-i}{2\left( s_{1}-s_{2}\right) \left( 1+is_{1}\right) }\left[ 1-\frac{z_{1}}{\sqrt{z^{2}_{1}-R^{2}\left( 1+s^{2}_{1}\right) }}\right] \\ \psi \left( z_{2}\right) & = & P\frac{+i}{2\left( s_{1}-s_{2}\right) \left( 1+is_{2}\right) }\left[ 1-\frac{z_{2}}{\sqrt{z^{2}_{2}-R^{2}\left( 1+s^{2}_{2}\right) }}\right] \label{equation array} \end{eqnarray} \end_inset \layout Standard \begin_inset Formula \begin{equation} \label{matrix} \left. \begin{array}{ccc} \varphi \left( z_{1}\right) & = & \displaystyle {P\frac{-i}{2\left( s_{1}-s_{2}\right) \left( 1+is_{1}\right) }\left[ 1-\frac{z_{1}}{\sqrt{z^{2}_{1}-R^{2}\left( 1+s^{2}_{1}\right) }}\right] }\\ \psi \left( z_{2}\right) & = & \displaystyle {P\frac{+i}{2\left( s_{1}-s_{2}\right) \left( 1+is_{2}\right) }\left[ 1-\frac{z_{2}}{\sqrt{z^{2}_{2}-R^{2}\left( 1+s^{2}_{2}\right) }}\right] } \end{array}\right\} \end{equation} \end_inset \the_end
