It does nor work.
It throws the error:

Exception in thread "main" java.lang.NoClassDefFoundError: org/apache/hadoop/io/Writable
        at java.lang.ClassLoader.defineClass1(Native Method)
        at java.lang.ClassLoader.defineClass(ClassLoader.java:621)
        at 
java.security.SecureClassLoader.defineClass(SecureClassLoader.java:124)
        at java.net.URLClassLoader.defineClass(URLClassLoader.java:260)
        at java.net.URLClassLoader.access$000(URLClassLoader.java:56)
        at java.net.URLClassLoader$1.run(URLClassLoader.java:195)
        at java.security.AccessController.doPrivileged(Native Method)
        at java.net.URLClassLoader.findClass(URLClassLoader.java:188)
        at java.lang.ClassLoader.loadClass(ClassLoader.java:307)
        at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301)
        at java.lang.ClassLoader.loadClass(ClassLoader.java:252)
        at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320)
Caused by: java.lang.ClassNotFoundException: org.apache.hadoop.io.Writable
        at java.net.URLClassLoader$1.run(URLClassLoader.java:200)
        at java.security.AccessController.doPrivileged(Native Method)
        at java.net.URLClassLoader.findClass(URLClassLoader.java:188)
        at java.lang.ClassLoader.loadClass(ClassLoader.java:307)
        at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301)
        at java.lang.ClassLoader.loadClass(ClassLoader.java:252)
        at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320)
        ... 12 more
Could not find the main class: Main.  Program will exit.

Do I need the hadoop library? This is not written in the requirements,...


Sean Owen wrote:
I think you probably want to study basic Java first then or you're
going to run into a lot more confusion.

Vector probabilities = new SparseVector();

is what you want. Interfaces and instantiating objects are the very
basics of Java.

On Fri, Sep 4, 2009 at 5:30 PM, Sven Boekhoff<[email protected]> wrote:
I never worked with interfaces.
And i also don't know what "instantiate an implementation" means.
How does it look like?

Sean Owen wrote:
Yes, Vector is an interface! You need to instantiate an implementation
like DenseVector.

On Fri, Sep 4, 2009 at 5:25 PM, Sven Boekhoff<[email protected]> wrote:
But i cant create an Vector object:

Vector probabilities = new Vector();

gives an error.

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