Hehe :) its good but the 'seq' program may contain loops and conditions.
finally i got the exact link which expected. http://stackoverflow.com/questions/4568645/printing-1-to-1000-without-loop-or-conditionals >Althaf's example is good, based on your conditions. You can call an external >program >to do this in GNU. The following will print it. > > >int main() >{ > system("seq 30000"); > } > > Regards, > Jos Collin >On Thu, Mar 31, 2011 at 07:59:01PM +0530, Faisal Fiza wrote: > > > > > > > > > > > > > > Recursion still has conditionals to check the exit condition, however goto > > is > > >not exactly a loop, moreover in > the question it doesnt mention program >should > > >terminate once 0 to 3.... is printed, ( word play :-D), either > recursion >or > > >goto will do, recursion will end up in stack over flow, goto will end up in > >infinite loop. ;-). >> >> >> Conditions: >> *Program should terminate after printed from 0 to 3lak. >> *No conditions and loops >> *If u use assembly , don't use conditional jumps. >> _______________________________________________ >> Indian Libre User Group Cochin Mailing List >> http://www.ilug-cochin.org/mailing-list/ >> http://mail.ilug-cochin.org/mailman/listinfo/mailinglist_ilug-cochin.org >> #[email protected] _______________________________________________ Indian Libre User Group Cochin Mailing List http://www.ilug-cochin.org/mailing-list/ http://mail.ilug-cochin.org/mailman/listinfo/mailinglist_ilug-cochin.org #[email protected] _______________________________________________ Indian Libre User Group Cochin Mailing List http://www.ilug-cochin.org/mailing-list/ http://mail.ilug-cochin.org/mailman/listinfo/mailinglist_ilug-cochin.org #[email protected]
