[ I am not on the list so please leave me in the CC on this thread ]
After doing this 'patch' you can specify a single %d anywhere in
subject_prefix (ie the 'Prefix for subject line of list postings') and it
will be magically replaced to the post_id (ie the message index).
BTW, where is the post_id stored? Can I updated it from the command line
with some (less)? standard tool?
I have tested with formats of type '[LIST (%d)]' for subject_prefix.
I would not be surprised if some strange formats may screw up my regular
expresions... today is my first day writing Python :)
Ex: Say you have a list with subject_prefix set to '[LIST (%d)]'
The first post will have a subject of:
Subject: [LIST (1)] the real subject line
The reply to this will hold:
Subject: Re: [LIST (2)] the real subject line
The reply to that will hold:
Subject: Re: [LIST (3)] the real subject line
And so on.
Regards,
Bart.
--
WebSig: http://www.jukie.net/~bart/sig/
--- CookHeaders.py- Fri Apr 27 20:58:32 2001
+++ CookHeaders.py Fri Apr 27 20:59:07 2001
@@ -47,13 +47,20 @@
# such as the list admin). We assume all digests have an appropriate
# subject header added by the ToDigest module.
prefix = mlist.subject_prefix
+ mprefix = re.escape(prefix)
+ if prefix and re.search(re.escape('%d'), prefix, re.I):
+ match = re.match(r"^(.*)"+re.escape("%d")+"(.*)$", prefix)
+ if match:
+ mprefix = re.escape(match.group(1))+"\d+"+re.escape(match.group$
+ prefix = prefix % mlist.post_id
# We purposefully leave no space b/w prefix and subject!
if not subject:
- del msg['subject']
- msg['Subject'] = prefix + _('(no subject)')
- elif prefix and not re.search(re.escape(prefix), subject, re.I):
- del msg['subject']
- msg['Subject'] = prefix + subject
+ msg['Subject'] = prefix + '(no subject)'
+ elif prefix:
+ match = re.match(r"^(.*)"+mprefix+"(.*)$", subject)
+ if match:
+ msg['Subject'] = match.group(1) + prefix + match.group(2)
+ else:
+ msg['Subject'] = prefix + subject
#
# get rid of duplicate headers
del msg['sender']
