Hi Rajeev, On Fri, 6 Jun 2014 15:54:03 +0530 Rajeev S <[email protected]> wrote: > The `list members of a list` feature is currently available as a part of > the users module, that takes list name as an argument. > > > show user –list [email protected] > > > This does not print the names of the list owners and moderators who are > not members of the list by default. They can be added to the list by > appending the `list.owners` and `list.moderators` to the member list. Is > there a necessity of a new command under the `list` scope that does the > same function? > > > show-members list [email protected]
I think it would be more intuitive to have this command in list scope rather than user scope. And anyway list scope must have a command to list all subscribers. > 1. > > Subscribe/Unsubscribe users from a list > > The commands suitably belongs to the user scope > > > subscribe user [email protected] –list [email protected] > > unsubscribe user [email protected] –list [email protected] Could it be used somehow to subscribe or unsubscribe more than one user? If it was like `subscribe list [email protected] --user/users user1/user1,user2,user3`. Or maybe some other way to do it in user scope itself? -- thanks, Abhilash Raj _______________________________________________ Mailman-Developers mailing list [email protected] https://mail.python.org/mailman/listinfo/mailman-developers Mailman FAQ: http://wiki.list.org/x/AgA3 Searchable Archives: http://www.mail-archive.com/mailman-developers%40python.org/ Unsubscribe: https://mail.python.org/mailman/options/mailman-developers/archive%40jab.org Security Policy: http://wiki.list.org/x/QIA9
