On 8/20/19 4:14 PM, Russell Clemings wrote: > This appears to do what I want -- removes everything except the names of > the list subscriptions: > > diff --git a/mailpasswds b/mailpasswds > index f194dc6..5f91f34 100644 > --- a/mailpasswds > +++ b/mailpasswds > @@ -151,19 +151,8 @@ def main(): > continue > # Group by the lower-cased address, since Mailman always > # treates per...@dom.ain the same as per...@dom.ain. > - try: > - password = mlist.getMemberPassword(member) > - except Errors.NotAMemberError: > - # Here's a member with no passwords, which I think was > - # possible in older versions of Mailman. Log this and > - # move on. > - syslog('error', 'password-less member %s for list %s', > - member, mlist.internal_name()) > - continue > - > - > - optionsurl = mlist.GetOptionsURL(member) > - > + password = '' > + optionsurl = '' > lang = mlist.getMemberLanguage(member) > info = (listaddr, password, optionsurl, lang) > userinfo.setdefault(member, []).append(info) > @@ -221,8 +210,7 @@ def main(): > i18n.set_language(poplang) > # Craft table header after language was set > header = '%-40s %-10s\n%-40s %-10s' % ( > - _('List'), _('Password // URL'), '----', '--------') > - > + _('Your subscriptions'), _(''), '----', ' ') > header = tounicode(header, enc) > # Add the table to the end so it doesn't get wrapped/filled > text += (header + '\n' + NL.join(table))
There are multiple ways to do this, but the above is as good as any. -- Mark Sapiro <m...@msapiro.net> The highway is for gamblers, San Francisco Bay Area, California better use your sense - B. Dylan ------------------------------------------------------ Mailman-Users mailing list Mailman-Users@python.org https://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: https://mail.python.org/mailman/options/mailman-users/archive%40jab.org