On Sun, Jan 27, 2002 at 01:25:27PM -0500, Tim Miller wrote: > I asked this before and got no answer. Don't know if I missed the reply or what. >Hard to believe that no one has wanted to do this. >
Everybody here is a volunteer. The questions that get answered are the ones that catch somebody's attention. > We are using Mailman 2.0.8 and have over 600 lists. I would like to get a listing >of the list names and their respective admin email addresses. I understand that this >will have to be done outside of the Mailman interface. > > I had hoped that there was a master file containing this information that I could >grep but if there is, I don't see it. > > Any help pointing me in the right direction is appreciated. I'd use the mailman bin program list_lists back-ended by a script to extract just the list names. Feed the list names to mailman's config_list program config_list -o - list-name and grep the standard output of that for "owner =". Print the result as a neat table. The whole thing could be done in perhaps thirty lines of bash, no doubt fewer lines of perl, perhaps a few lines more of python. Of course, some mailman user more weighty than I know doubt knows a much simpler way. -- ----------------------------------------------------------------- Dan Wilder <[EMAIL PROTECTED]> Technical Manager & Editor SSC, Inc. P.O. Box 55549 Phone: 206-782-8808 Seattle, WA 98155-0549 URL http://embedded.linuxjournal.com/ ----------------------------------------------------------------- ------------------------------------------------------ Mailman-Users maillist - [EMAIL PROTECTED] http://mail.python.org/mailman/listinfo/mailman-users
