Xiaoyan Ma wrote:
>I need a script that gets all lists' subscribe_policy/unsubscribe_policy and
>outputs to a file.
> Similar to lists_admins, but instead of getting administrator's email
> address, it gets
>subscribe_policy. I looked into MailList.py, config_list, list_lists and
>withlist ... but have
>not figured out how to do it. Can someone point me to the right direction?
Since you want something similar to list_admins, look at that. In
particular find
owners = COMMASPACE.join(mlist.owner)
print _('List: %(listname)s, \tOwners: %(owners)s')
You don't need COMMASPACE.join(mlist.owner) because subscribe policy is
a number, not a list of e-mail addresses, but if you are going to use
the i18n._ method you do have to assign mlist.subscribe_policy to a
variable or you can just
print 'List: %s, \tPolicy: %d' % (listname,
mlist.subscribe_policy)
--
Mark Sapiro <[EMAIL PROTECTED]> The highway is for gamblers,
San Francisco Bay Area, California better use your sense - B. Dylan
------------------------------------------------------
Mailman-Users mailing list
Mailman-Users@python.org
http://mail.python.org/mailman/listinfo/mailman-users
Mailman FAQ: http://www.python.org/cgi-bin/faqw-mm.py
Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/
Unsubscribe:
http://mail.python.org/mailman/options/mailman-users/archive%40jab.org
Security Policy:
http://www.python.org/cgi-bin/faqw-mm.py?req=show&file=faq01.027.htp
